In 1992 maurizio damilano ,of italy walked 29752m in 2.00h( a) calcula damilano's average in m/s. suppose damilano slows down to 3.00m/s at the midpoint in this journey but then picks up the pace and accelerate to the speed calculated in (a).it takes damilano 30.0 s to accelerate .find the magnitude of the average acceleration during this time interval

Answers:

a)

b)

Explanation:

a) Average velocity is expressed by the following equation:

Where:

is Maurizio's displacement

is the time

Hence:

b) Average acceleration is the variation of velocity over a specified period of time :

Where:

being the initial velocity and the final velocity

Then:

electric

explanation:

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14