The magnitude of the force that a spring exerts (f) when it is stretched a distance x from its unstressed length is governed by hooke's law, f = kx. (a) what are the dimensions of the force constant, k? (use the following as necessary: m for mass, t for time, and l for length.)

k =  M / T^2

Explanation:

Hooke's law states that the lengthening of a spring is directly proportional to the force module applied to it, provided that the spring is not permanently deformed.

F = k * L

So:

k = F / L

Where :

[F] = N (Newton units)

[L] = m (meter)

[k] = N / m

N = ( M * L ) / T^2

[N] = ( kg * m ) / s^2

Finally:

[k] = ( kg * m ) / ( m * s^2 )

[k] = kg / s^2

k = M / T^2

d eras and periods