Particle 1 and particle 2 have masses of m1 = 2.2 × 10-8 kg and m2 = 4.8 × 10-8 kg, but they carry the same charge q. the two particles accelerate from rest through the same electric potential difference v and enter the same magnetic field, which has a magnitude b. the particles travel perpendicular to the magnetic field on circular paths. the radius of the circular path for particle 1 is r1 = 8 cm. what is the radius (in cm) of the circular path for particle 2?

Explanation:

Given

same charge on both masses

potential Energy due to Magnetic Field =Kinetic Energy of Particle

and we know

Force due to magnetic field will Provide centripetal Force

and B is equal for both particles

thus

the device is called “ rocket engine”

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.