Abook is pushed with an initial horizontal velocity of 5.0 meters per second off the top of a 1.19 meter high desk. how far away does the book land?

2.45 m

Explanation:

First of all, we have to calculate the time of flight of the book, by using the equation for the vertical motion:

where

h = 1.19 m is the vertical distance covered by the book

g = 9.8 m/s^2 is the acceleration of gravity

t is the time of flight

Solving for t,

Now we can find the horizontal distance covered by the book, which is given by

where

is the horizontal velocity

t = 0.49 s is the time of flight

Substituting,

So the book lands 2.45 m away.

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