61. a sandal is dropped from the top of a 15.0-m-high mast on a ship moving at 1.75 m/s due south. calculate the velocity of the sandal when it hits the deck of the ship: (a) relative to the ship and (b) relative to a stationary observer on shore. (c) discuss how the answers give a consistent result for the position at which the sandal hits the deck.

Answered

Explanation:

u = 1.75 m/s

h = 15 m

Now, for the magnitude of velocity when hitting the deck

Using third equation of motion

v^2 - 1.75^2 = 2×9.8×15

v = 17.15 m/s

the velocity of sandal when it hits the deck is 17.15 m/s this the velocity of sandal relative to the ship

b) velocity relative to a stationary observer on shore

=

=17.23 m/s

To a person aboard the ship, they see the sandal land directly below the release point. A stationary observer on the outside sees the same thing, except the fact that  the landing point has translated to the south.

answer; ///(74) degrees is your answer..