A0.41-kg particle has a speed of 5.0 m/s at point a and kinetic energy of 8.5 j at point b. (a) what is its kinetic energy at a? j (b) what is its speed at point b? m/s (c) what is the total work done on the particle as it moves from a to b?

A)The kinetic energy at a point A when a particle of .41 kg moves at a speed of 5.0 m/s is 5.125 J.

B)The speed at point B of the particle of .41 kg with Kinetic Energy 8.5 J is 6.44 m/s.

C)The total Work done by the particle is 3.375 J.

A)Explanation

From the given statements, we know  

Mass (m) = 0.41 kg

Velocity = 5.0 m/s

As we know Kinetic Energy (KE) =

Substituting the values in the above equation, we find

Kinetic Energy (KE) =

= 5.125 joule

(b) Explanation

From the given statements, we know  

Mass (m) = 0.41 kg

Kinetic Energy (KE) = 8.5 J

As we know Kinetic Energy (KE) =

Substituting the values in the above equation, we find

Kinetic Energy (KE) = = 8.5 J

Or, = =

Or, v = =6.439 m/s ~ 6.44 m/s

(c) Explanation

From the above given statements, we know  

Kinetic Energy at A = 5.125 J

Kinetic Energy at B = 8.5 J

As we know

Work Done = Change in Kinetic Energy (ΔKE)

So, Work Done (WD) = Kinetic Energy at B - Kinetic Energy at A

 WD = (8.5 – 5.125) J = 3.375 J

area of focus

i'm on my way to history not a mistory.