Afather demonstrates projectile motion to his children by placing a pea on his fork's handle and rapidly depressing the curved tines, launching the pea to heights above the dining room table. suppose the pea is launched at 7.39 m/s at an angle of 69.0° above the table. with what speed (in m/s) does the pea strike the ceiling 1.90 m above the table?

4.17 m/s

Explanation:

To solve this problem, let's start by analyzing the vertical motion of the pea.

The initial vertical velocity of the pea is

Now we can solve the problem by applying the suvat equation:

where

is the vertical velocity when the pea hits the ceiling

is the acceleration of gravity

s = 1.90 is the distance from the ceiling

Solving for ,

Instead, the horizontal velocity remains constant during the whole motion, and it is given by

Therefore, the speed of the pea when it hits the ceiling is

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electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j