Aboat has a mass of 4900 kg. its engines generate a drive force of 4600 n due west, while the wind exerts a force of 670 n due east and the water exerts a resistive force of 1170 n due east. take west to be the positive direction. what is the boat's acceleration, with correct sign?

a = +0.56 m/s²  (due west)

Explanation:

We apply Newton's second law:  

∑Fx = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)  

m : mass in kilograms (kg)  

a : acceleration in meters over second square (m/s²)  

Data:  

m=  4900 kg

Fd= 4600 N : drive force

Fw = 670 N :  wind force

Fr = 1170 N : water resistive force

Problem development

We apply the formula (1)

∑Fx = m*a

Fd-Fw-Fr = m*a

4600 - 670 - 1170 =  4900 *a

2760 =  4900 *a

a= (2760) / ( 4900 )

a = +0.56 m/s² (due west)

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

overcharge is the right answer system