Aparticle with charge − 5.20 nc is moving in a uniform magnetic field b⃗ =−( 1.24 t )k^. the magnetic force on the particle is measured to be f⃗ =−( 4.00×10−7 n )i^+( 7.60×10−7 n )j^. a calculate the x-component of the velocity of the particle.

b calculate the y-component of the velocity of the particle.

c calculate the scalar product v⋅f

d what is the angle between v and f ? give your answer in degrees.

c. rb

explanation:

the atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.

the answer is a. at the equator

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explanation:

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s