Acrazy dog runs at a constant speed of 19.85 mi/hr for 6.09 min. how far does the dog travel during this time period?

Distance, d = 3242.19 meters

Explanation:

It is given that,

Speed of the dog, v = 19.85 mi/hr

Since, 1 mph = 0.44704 m/s

v = 19.85 mi/hr = 8.873 m/s

Time taken by the dog, t = 6.09 min = 365.4 sec

Let the distance covered by the dog during this time period is d. It can be calculated by the speed of the dog multiplied by the time taken as :

d = 3242.19 meters

So, the the dog travel during this time period is 3242.19 meters. Hence, this is the required solution.

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//