Aforce vector has a magnitude of 579 newtons and points at an angle 38.0° of below the positive x axis. (a) what is the the x scalar component of the vector?
fx = n

(b) what is the y scalar component of the vector?
fy = n

a) x- component of force = 432.62 N

b)y- component of force = 338 N

Explanation:

given,

magnitude of force = 549 N

angle between the force vector with positive horizontal x-axis(∅) = 38.0°

a) x-scalar component of the force vector

       x- component of force = F cos ∅

       x- component of force = 549 cos 38°

      x- component of force = 432.62 N

b) y-scalar component of the force vector

       y- component of force = F sin ∅

       y- component of force = 549 sin 38°

      y- component of force = 338 N

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