Apenguin slides at a constant velocity of 1.43 m/s down an icy incline. the incline slopes above the horizontal at an angle of 6.47°. at the bottom of the incline, the penguin slides onto a horizontal patch of ice. the coefficient of kinetic friction between the penguin and the ice is the same for the incline as for the horizontal patch. how much time is required for the penguin to slide to a halt after entering the horizontal patch of ice?

t =1.285  s

Explanation:

u=1.43 m/s

∅=6.47°

We know that  μ(k)=tan∅

F(net)=-f(k)

ma =μ(k)*m*g

a =μ(k)*g   equation 1

v=u+at

0=u+(μ(k)*g*t

Putting values

t=u/(g*tan∅)

t=

t=1.285 s

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: