A5-kg fish swimming 1 m/s swallows an absent minded 1-kg fish swimming toward it at a speed that brings both fish to a halt immediately after lunch. show that the speed of the approaching smaller fish before lunch must have been 5 m/s.

Explanation:

If we call the big fish as 1 and the small one as 2 we write their initial linear momentum as:

While their final linear momentum will be (since both are together we call their final velocity v):

But their final velocity is 0, so , and since linear momentum must be conserved we have , which means:

We want the speed of the approaching smaller fish (), so:

And just substitute our values:

Where the minus sign indicates that the small fish goes in the opposite direction as the big fish.

i would think it's food chain

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min