Astudent uses a spring to launch a marble vertically in the air. the mass of the marble is 0.002 kg and
when the spring is stretched 0,05 m it exerts a force of 10 n. what is the maximum height the marde can
reach?

25 m

Explanation:

Work to compress spring = gravitational potential energy of marble

W = PE

Fd = mgh

h = Fd / (mg)

Given F = 10 N, d = 0.05 m, m = 0.002 kg, and g = 10 m/s²:

h = (10 N) (0.05 m) / (0.002 kg × 10 m/s²)

h = 25 m

25 m

Explanation:

A student uses a spring to launch a marble vertically in the air. The mass of the marble is 0.002 kg and  when the spring is stretched 0,05 m it exerts a force of 10 N. Therefore, the maximum height the marde can  reach is 25 m.

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

the answer would most likely be c, because if it's a comical piece of information, it may likely not be true, if it's a site that allows anybody to edit the content, it could mean a five year old is typing the info, and if it's a tv show produced by a celeb, it may have a biased opinion.