In the 1991 world track and field championships in tokyo, mike powell jumped 8.95 m, breaking by a full 5 cm the 23-year long-jump record set by bob beamon . assume that powell's speed on takeoff was 9.5 m/s (about equal to that of a sprinter) and that g = 9.80 m/s2 in tokyo. how much less was powell's horizontal range than the maximum possible horizontal range for a particle launched at the same speed?

0.26 m

Explanation:

θ = Angle at which the jumper launched

g = Acceleration due to gravity = 9.8 m/s²

R = Range = 8.95 m

v = Velocity of the jumper = 9.5 m/s

Range of projectile

When, θ = 45° maximum range is obtained

sin(2×45) = sin90 = 1

Maximum range

So, Mike Powell jumped 9.21-8.95 = 0.26 m less than the maximum range if launched at the same speed.

what is the question because that is not a question.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer