An average human weighs about 650 n. if each of two average humans could carry 1.0 c of excess charge, one positive and one negative, how far apart would they have to be for the electric attraction between them to equal their 650@n weight?

Distance, r = 3721.04 meters

Explanation:

It is given that,

Charges on both humans,

Electric force of attraction between them, F = 650 N

We need to find the separation between two humans. It can be solved using the following formula as :

r = 3721.04 meters

So, the distance between the humans is 3721.04 meters. Hence, this is the required solution.

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