Arifle is aimed horizontally at a target 55.0 m away. the bullet hits the target 2.90 cm below the aim point. you may want to review (pages 86 - 90) . part a what was the bullet's flight time? express your answer with the appropriate units. nothing nothing request answer part b what was the bullet's speed as it left the barrel? express your answer with the appropriate units. nothing nothing request answer

a) t = 0.07615s

b) V = 722.26m/s

Explanation:

For movement on the y-axis:

   Where ΔY = -0.029m; Vy = 0

Solving for t:

t = 0.07615s

Now, having the flight time of the bullet, we calculate the speed with x-axis equations:

X = V*t   where X=55m;  t = 0.07615s  Solving for V:

V = 722.26m/s

an obstruction

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!