Kalea throws a baseball directly upward at time t = 0 at an initial speed of 13.7 m/s. how high h does the ball rise above its release point? ignore air resistance and use g = 9.80 m/s^2.

h = 9.57 seconds

Explanation:

It is given that,

Initial speed of Kalea, u = 13.7 m/s

At maximum height, v = 0

Let t is the time taken by the ball to reach its maximum point. It cane be calculated as :

t = 1.39 s

Let h is the height reached by the ball above its release point. It can be calculated using second equation of motion as :

Here, a = -g

h = 9.57 meters

So, the height attained by the ball above its release point is 9.57 meters. Hence, this is the required solution.

a person with a mass of 106kg has a weight of 1060n

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.