Astone thrown off a bridge 10m above a river has an initial velocity of 8ms at an angle of 25 degrees above the horizontal. what is the range of the stone?

Explanation:

It is given that,

Height above which the stone was thrown, h = 10 m

Initial velocity of the stone, u = 8 m/s

Angle above the horizontal,

The horizontal component of velocity is,

The vertical component of velocity is,

Let t is the time of flight in vertical motion. The second equation of motion is :

t = 0.34 seconds

Let s is the range of the stone. It can be calculated as :

s = 2.46 meters

So, the range of the stone is 2.46 meters. Hence, this is the required solution.

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