Two protons are released from rest, one from location 1 and another from location 2. when these two protons reach location 3, the first proton has a speed that is 2 times the speed of the second proton. if the electric potentials at locations 1 and 2 are 231 v and 115 v, respectively, what is the electric potential at location 3?

76.66V

Explanation:

Accorging to law of conservation of energy:

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Since the protons are released from rest, the initial kinetic energy is zero and the electric potencial energy is given by:

Now from , we have:

Recall that , replacing:

Rewriting (1) for :

Now, equaling (2) and (3):

Finally, rewriting for

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.

0.55x745.7j and a calculator