Acar is initially driving at 30 m/s. it hits a large pothole, after which it is traveling in the same direction but at 25 m/s. draw vectors representing the initial velocity final velocity, and (hange in velocity which describe the equation : + δ¡. 2. the si nit for weight is the newton (not the express the weight of a 2.8 lbs. watermelon in newtons. 3. on mars gravitational acceleration is amars 3.71 m/s2 or amars 0.37g, where g is the gravitational acceleration of on object on earth. if a future astronaut drops a rock from a height of 1.9 m how long will it take to hit the ground on mars? compare that number to how long the same rock would take to fall on earth.

The time of Mars is 1.65 times larger on Mars than on Earth

Explanation:

The equation that describes the system is the final speed is equal to the speed minos the speed lost by the collision with the porhole

       Vf = Vo - V pothole

B) let's transform the weight of free groin system and N international system

      1 N = 0.2248 lb

      2.8 lbs (1N / 0.2248lbs) = 12.5 N

c) Kinematic equations are the same in all inertial systems, Mars and Earth, so we can use the height equation, with zero initial velocity

        Y = Vo t - ½ g t²

        Y = - ½ g t²

        t = √ 2Y / g

Mars

         gm = 0.37g

         gm = 0.37 9.8

         gm = 3,626 m / s²

         t = √( 2 1.9 / 3.626 )

         t = 1.02 s

Earth

         t = √( 2 1.9 / 9.8)

         t = 0.62 s

To make the comparison of time we are the relationship between the two

         tm / te = 1.02 / 0.62

         tm / te = 1.65

The time of Mars is 1.65 times larger on Mars than on Earth

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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