Amortar is like a small cannon that launches shells at steep

angles. a mortar crew is positioned near the top of a steep

hill. enemy forces are charging up the hill and it is

necessary for the crew to spring into action. angling the

mortar at an angle of 0 = 49.0° (as shown), the crew fires

the shell at a muzzle velocity of 182 ft/s.

how far d down the hill does the shell strike if the hill

subtends an angle 0 = 38.0° from the horizontal? ignore

air friction.