(1.) an object accelerates from rest with a constant acceleration of 2 m/s2. how far will it have
moved after 9s?

81 m

Explanation:

Given:

v₀ = 0 m/s

a = 2 m/s²

t = 9 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (9 s) + ½ (2 m/s²) (9 s)²

Δx = 81 m

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.