Physics, 02.10.2019 19:30 hannnahbeela

How are the outer planets different from the inner planets of our solar system?

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The outer planets are further away, larger and made up mostly of gas. The inner planets (in order of distance from the sun, closest to furthest) are Mercury, Venus, Earth and Mars. After an asteroid belt comes the outer planets, Jupiter, Saturn, Uranus and Neptune.

Explanation:

Answer from: sin91

There are eight planets in the solar system. Four of them are inner and other four are outer planets.

→Outer planets lie beyond asteroid belt.

→Outer planets are gaseous planets and are referred as Jovian planets. Inner planets are terrestrial planets.

→Outer planets have many number of moons where as inner planets have zero to two moons.

→Inner planets lie closer to the Sun as compared to Outer planets.

→Outer planets are larger in size than inner planets.

→ Outer planets have larger orbital period than inner planets.

→Outer planets have ring system unlike inner planets.

Answer from: Quest

It's because 3 if it was 10 it wouldn't look right do it goes up to 4d

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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