The table below shows data of sprints of animals that traveled 75 meters. at each distance marker, the animals' times were recorded. which animal is showing the greatest average acceleration from the 25-meter mark to the 50-meter mark?

Animal 2 has maximum acceleration from x = 25 to x = 50

Explanation:

For animal 1

Average velocity at t = 3.5 s

Average velocity at t = 3 s

so average acceleration is given as

For animal 2

Average velocity at t = 5.5 s

Average velocity at t = 4.5 s

so average acceleration is given as

For animal 3

Average velocity at t = 9 s

Average velocity at t = 7 s

so average acceleration is given as

For animal 4

Average velocity at t = 11 s

Average velocity at t = 6 s

so average acceleration is given as

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge