Asailboat has a mass of 1.20 ✕ 103 kg and is acted on by a force of 2.90 ✕ 103 n toward the east, while the wind acts behind the sails with a force of 3.90 ✕ 103 n in a direction 45° north of east. find the magnitude (in m/s2) and direction (in degrees north of east) of the resulting acceleration.

a = 4.04 m/s2

north of east

Explanation:

The mass of the boat is m = 1200 kg

The forces acting  due to wind on the boat is Fwind = 3900 N j^ (north)

and The forces acting due to water  on the boat is Fwater = 2900 N i^ (east)

The net force on the boat is F = 2900 N i^ + 3900 N j^

The horizontal component of the net acceleration is ax = Fwater/m = 2.41 m/s2

vertical component of the net acceleration is ay = Fwind/m = 3.25 m/s2

Net acceleration is

a = 4.04 m/s2

The direction of the net acceleration is =

=north of east

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.