On december 10, 1954, stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.00 s, and was brought jarringly back to rest in only 1.40 s! calculate his (a) acceleration and (b) deceleration. express each in multiples of g (9.80 m/s2) by taking its ratio to the acceleration of gravity.

Explanation:

Given

Initial velocity(u)=0

Final Velocity(v)=282 m/s

time taken=5 s

acceleration to acquire 282 m/s

a=5.74g

(b)deceleration

It comes to rest in 1.4 s

initial velocity of Just before deceleration is 282 m/s

v=u+at

a in terms of g

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

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okay, ima .

um it shows links to uh so kinda microsoft website is that were ima go or no? ?