Assume: a 78 g basketball is launched at an angle of 45.3 ◦ and a distance of 19.6 m from the basketball goal. the ball is released at the same height (ten feet) as the basketball goal’s height. a basketball player tries to make a long jump-shot as described above. the acceleration of gravity is 9.8 m/s 2 . what speed must the player give the ball

Initial speed = v₁ = 13.86 m/s

Explanation:

This problem is related to the projectile motion. Projectile motion is a two dimensional motion having horizontal and vertical component. Horizontal component of the velocity remain constant throughout his motion while vertical component vary with time.  

Given data :

Mass = m = 78 g

Angle = θ = 45.3°

Range = R = 19.6 m

Gravitational acceleration = g = 9.8 m/s²

Initial velocity = v₁ = ?

Using the formula of range of the projectile

θ

v₁² = 192.09

v₁ = 13.86 m/s

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.