Balls 1 and 2 are each thrown horizontally from the same height above level ground, but ball 2 has a greater initial velocity after leaving the thrower’s hand. if air resistance is negligible, how do the accelerations of the balls and the times it takes them to hit the ground compare?

The acceleration and time of motion for the two balls is the same since they have zero initial vertical velocity.

The vertical height traveled by the balls is calculated as follows;

For the first ball;

For the second ball;

Thus, we can conclude that the acceleration and time of motion for the two balls is the same since they have zero initial vertical velocity.

Learn more here:link

Acceleration and time will be same for both balls.

Explanation:

Given that ball is thrown horizontally

Lets take both balls are at a height of h from ground level.

Lets take initial velocity of ball 1 = u

Lets take initial velocity of ball 2 = v

Given that v>u.

Initially the component of velocity in vertical direction is zero.

so

So time to reach at ground will be same for both the balls.

We know that acceleration due to gravity is also same for both the balls.Acceleration for both ball will be g.

1 the 4 is sig

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.