Physics, 28.09.2019 20:30 Auttyrain7596
The specific volume of 5 kg of water vapor (h2o) at 1.5 mpa, 440 °c is 0.2160 m/kg. (this could be the condition exiting a boiler in a steam power plant.) we'll learn how to use the "steam tables" to find this information in a couple of weeks.) determine (a) the volume in m, occupied by the water vapor, (b) the amount of water vapor present in gmol and (c) the number of molecules. recall that avagodro's number is na 6.024x1023 molecules/gmol (6.023x 1 026 molecules/kmol). also, the molecular weight of water is very closed to 18.0 g/gmol (kg/kmol). [ans: (a) v 1.08 m] repeat your calculations if the 5 kg of water (h2o) is cooled to a temperature of 40 °c, such that the specific volume is reduced to 0.001007 m/kg. the pressure is still .5 mpa. (this could be the condition entering a boiler in a steam power plant.)
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Steam is generated in a boiler of a cogeneration plant at 10 mpa and 450°c at a steady rate of 5 kg/s. in normal operation, steam expands in a turbine to a pressure of 0.5 mpa and is then routed to the process heater, where it supplies the process heat. steam leaves the process heater as a saturated liquid and is pumped to the boiler pressure. in this mode, no steam passes through a condenser, which operates at 20 kpa. (a) determine the power produced in the turbine and the rate at which process heat is supplied in this mode. (b) determine the power produced in the turbine and the rate of process heat supplied if only 60 percent of the steam is routed to the process heater and the remainder is expanded to the condenser pressure. (3.32 mw; 9.69 mw; 4.25 mw; 5.82 mw)
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The specific volume of 5 kg of water vapor (h2o) at 1.5 mpa, 440 °c is 0.2160 m/kg. (this could be t...
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