The lighting needs of a storage room are being met by six fluorescent light fixtures, each fixture containing four lamps rated at 60 w each. all the lamps are on during operating hours of the facility, which is 6 a. m. to 6 p. m., 365 days a year. the storage room is actually used for an average of 3 h a day. if the price of electricity is $0.11/kwh, determine the amount of energy and money that will be saved as a result of installing motion sensors. also, determine the simple payback period if the purchase price of the sensor is $32 and it takes 1 h to install it at a cost of $66.

amount of energy  = 4730.4 kWh/yr

amount of money = 520.34 per year

payback period = 0.188 year

Explanation:

given data

light fixtures = 6

lamp = 4

power = 60 W

average use = 3 h a day

price of electricity = $0.11/kWh

to find out

the amount of energy and money that will be saved and simple payback period if the purchase price of the sensor is $32 and it takes 1 h to install it at a cost of $66

solution

we find energy saving by difference in time the light were

ΔE = no of fixture × number of lamp × power of each lamp × Δt

ΔE is amount of energy save and Δt is time difference

so

ΔE = 6 × 4 × 365 ( 12 - 9 )

ΔE = 4730.4 kWh/yr

and

money saving find out by energy saving and unit cost that i s

ΔM = ΔE × Munit

ΔM = 4730.4 × 0.11

ΔM = 520.34 per year

and

payback period is calculate as

payback period =

payback period =

payback period = 0.188 year

i need with 1.3.2 investigate cycling o2 and co2 apex

we need to see it