At one point in a pipeline, the water speed is 1.8 m/s, and the gauge pressure is 51500 pa. find the gauge pressure (in pa) at a second point in the line 11.5 m lower than the first if the pipe diameter at the second point is twice that at the first. use a density of water 1000 kg/m3.

pressure in the second point is P₂ = 165833.75 Pa

Explanation:

given,

water speed = 1.8 m/s

gauge pressure(P₁) = 51500 Pa

gauge pressure at another point (P₂) = ?

distance of the point at 11.5 m

density of the water = 1000 kg/m³

diameter of the second pipe  is double than first.

A₁ V₁ = A₂ V₂

π r² ×  1.8 = π × (2r)² ×  V₂

V₂ = 0.45 m/s

now, gauge pressure at P₂

P₂ = 165833.75 Pa

pressure in the second point is P₂ = 165833.75 Pa

i would think klcio3

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day