Acannon sends a projectile towards a target a distance 1420 m away. the initial velocity makes an angle 35◦ with the horizontal. the target is hit. the acceleration of gravity is 9.8 m/s2 . what is the magnitude of the initial veloc- ity?

Explanation:

From the exercise we know the final x distance, the angle which the projectile is being released and acceleration of gravity

From the equation of x-position we know that

Solving for

(1)

Now, if we analyze the equation of y-position we got

At the end of the motion y=0

Knowing the equation for in (1)

Solving for t

Now, we can solve (1)

121.7 m/s

Explanation:

Horizontal range, R = 1420 m

Angle of projection, θ = 35°

acceleration due to gravity, g = 9.8 m/s^2

let u be the velocity of projection.

Use the formula for horizontal range

u = 121.7 m/s

Thus, the velocity of projection is 121.7 m/s.

your answer is c! hope this : )

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min