Abulldozer does 4,500 j of work to push a mound of soil to the top of a ramp that is 15 m high. the ramp is at an
angle of 35° to the ground. how much force did the bulldozer apply to the mound of soil? round your answer to two
significant figures.
its 520 n

520 N

Explanation:

Work is the dot product of the force vector and displacement vector.

W = F · x

This means it is the product of the magnitudes of the vectors and the cosine of the angle between them.

W = F x cos θ

The displacement of the soil is 15 m up.  The force is parallel to the ramp.  So the angle between the vectors is 90° − 35° = 55°.

Plugging in the values and solving for F:

4500 J = F (15 m) (cos 55°)

F = 523 N

Rounded to two significant figures, the force is 520 N.

yup its correct its: c) b b

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.