Two masses are attracted by a gravitational force of 7 n.
(a) what will the force of attraction be if the distance between these two masses is quartered?

The answer to your question is: F  = 0.4375 N. The force will be 16 times lower than with the first conditions.

Explanation:

Data

F = 7 N

F = ?  if the masses is quartered

Formula

Process

Normal conditions F = Km₁m₂/r²  = 7              

When masses quartered        F = K(m₁/4)(m₂/4)/r²  = ?

                                                F = K(m₁m₂/16)/r²

                                                F = K(m₁m₂/16r²      = 7/16  = 0.4375 N

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete

so easy. just google the electromagnetic waves and it’ll pop up.