Abeam of electrons with energy 250 me v is elastically scattered through an angle of 10° by a heavy nucleus that is at rest. it is found that the differential cross-section is 65% of that expected for scattering from a point-nucleus. estimate the root mean square radius of the nucleus. neglect the recoil of the nucleus and use the rest mass of the electron as 0.511 mev/c

true

explanation:

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

earth's neighboring galaxy, the andromeda galaxy, is a distance of 2.54×107 light-years from earth. if the lifetime of a human is taken to be 70.0 years, a spaceship would need to achieve some minimum speed min to deliver a living human being to this galaxy.