Apackage is dropped from a helicopter that is moving upward at 15 m/s.
if it takes 8.0s before the package strikes the ground, how high above the ground was the package when it was released?

193.6 m.

Explanation:

Consider upward direction as negative and downward direction as positive. Initial velocity in vertical velocity of the package = -15 m/s

Time taken by the package to reach the ground = 8.0 s

Acceleration due to gravity will act in downward direction.

Use the second equation of motion:

s = u t + 0.5 at²

where, s is the displacement, u is the initial velocity, t is the time and a is the acceleration.

Substitute the values:

s = (-15)(8)+ 0.5 (9.8)(8.0)² = 193.6 m

the independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.

the dependent variable, the one that you measure the response in, is the distance that the washers travel.