Abaseball slugger hits a pitch and watches the ball fly into the bleachers for a home run, landing h = 9.5 m higher than it was struck. when visiting with the fan that caught the ball, he learned the ball was moving with final velocity vf = 30.15 m/s at an angle θf = 29° below horizontal when caught. assume the ball encountered no air resistance, and use a cartesian coordinate system with the origin located at the ball's initial position.

The ball's position can get of the initial angle when leave the bat and velocity magnitud.

θ = 35,1

v = 36,5

Explanation:

θf= 29

h= 9,5 m

vf= 30,15

Now as you know the vector in 'y' can be related with Tan function

So, the initial velocity in 'y' can be resolved:

Finally the velocity is going to be:

θ

θ

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂