Apiece of glass of index of refraction 1.50 is coated with a thin layer of magnesium fluoride of index of refraction 1.38. it is illuminated with light of wavelength 680 nm. determine the minimum thickness of the coating that will result in no reflection

123.18 nm

Explanation:

Given:

Let t be the thickness of the film. The relation between the wavelength of light  in film and thickness of the film  in order to have no reflection is given  by

Now According to question we have

where n is the refractive index of the film.

Now thickness t is given by

Hence the thickness of the film is calculated in order to have no reflection.

does anyone know or what?

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this