An electric field of 790,000 n/c points due west at a certain spot. what is the magnitude of the force that acts on a charge of -3.00 uc at this spot? (14c = 10 6c) give your answer in sl unit rounded to two decimal places.

2.37 N.

Explanation:

According to Coulomb's law, the magnitude of electrostatic force of interaction between two static point charges and , separated by a distance , is given by

where, = Coulomb's constant.

The direction of this force is along the line joining the two charges, from positive to negative charge.

The electric field at a point is defined as the amount of electrostatic force experienced per unit small positive test charge, placed at that point.

Therefore,

We have,

Therefore, the electric force at that point is given by

The negative sign indicates that the force is attractive in nature.

Thus, the magnitude of this force = 2.37 N.

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