Apolice officer is driving due north at a constant speed of 29 m/s rel- ative to the ground when she notices a truck on an east–west highway ahead of her, driving west at high speed. she finds that the truck’s speed relative to her car is 48 m/s (about 110 mph). (a) sketch the vector trian- gle that shows how the truck’s velocity relative to the ground is related to the police car’s velocity relative to the ground and to the truck’s veloc- ity relative to the police car. the sketch need not be to scale, but the ve- locity vectors should be oriented correctly and bear the appropriate labels. (b) what is the truck’s speed, relative to the ground?

The truck’s speed, relative to the ground = 38.25 ms⁻¹

Explanation:

As per the question,

Given data:

Velocity of car with respect to ground = 29 ms⁻¹

Velocity of truck with respect to car = 48 ms⁻¹

so

now

Using the vector sum property in the vector triangle, we can say

As we have given the magnitude of velocities

Now,

By using Pythagoras theorem in triangle AOB

OA² + OB² = AB²

OA = √(48² - 29²) = 38.25 ms⁻¹

Therefore, the truck’s speed, relative to the ground = 38.25 ms⁻¹

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.