Aconvex mirror has a radius of 20 cm. an object is placed 50 cm from the mirror. find the location of the image, the magnification, and the type of image formed. 2. for the previous mirror system, draw the three principle rays and compare your results to that obtained for the previous problem. 3. a convex mirror has a radius of 60 cm. an object is placed 200 cm from the mirror. find the location of the image, the magnification, and the type of image formed. for the previous mirror system, draw the three principle rays and compare your results to that obtained for the previous problem.

Explanation:

R = Radius of curvature = 20 cm

Focal length = f = R/2 = 20/2 = 10 cm

f = -10 cm (convex mirror)

u = Object distance =  50 cm

Lens Equation

Image is 8.33 cm behind the mirror

As, the sign is negative the image is behind the mirror and is virtual in nature

Magnification is 0.166

Positive magnification indicates the image is upright.

R = Radius of curvature = 60 cm

Focal length = f = R/2 = 60/2 = 30 cm

f = -30 cm (convex mirror)

u = Object distance =  200 cm

Lens Equation

Image is 26.08 cm behind the mirror

As, the sign is negative the image is behind the mirror and is virtual in nature

Magnification is 0.13

Positive magnification indicates the image is upright.

the second one and the forth one are in the purple because they are opinions and the rest are in the yellow

explanation:

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s