Auniform disk (i =½ mr2 ) of mass 8.0 kg can rotate without friction on a fixed axis. a string is wrapped around its circumference and is attached to a 6.0 kg mass. the string does not slip. what is the tension in the cord while the mass is falling?

T = 23.54 N

Explanation:

Given,

Let 'T' be the tension in the string and 'a' be the acceleration of the block,

Hence, the angular acceleration of the pulley =

From the f.b.d. of the mass

From the f.b.d. of the pulley,

From the eqn (1) and (2), we get,

Hence, the tension in the cord while the mass is falling is 23.54 N

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

it's when something is going so fast it makes a loud noise, breaking the sound barrier, for example: a jet makes a loud noise, not only cause of the jet but because they reached a point where they went so fast that you can year the noise from various parts, kinda like a police car, lets say the car was going   so fast that you hear the siren of the cop car right next to you, but the car is probably a mile a way, it's cos the siren was next to you a few seconds if you understand me