Physics, 19.09.2019 21:00 kandrews6221
Coulomb's law for the magnitude of the force f between two particles with charges q and q′ separated by a distance d is |f|=k|qq′|d2, where k=14πϵ0, and ϵ0=8.854×10−12c2/(n⋅m2) is the permittivity of free space. consider two point charges located on the x axis: one charge, q1 = -18.5 nc , is located at x1 = -1.705 m ; the second charge, q2 = 31.5 nc , is at the origin (x=0.). part a what is the net force exerted by these two charges on a third charge q3 = 45.0 nc placed between q1 and q2 at x3 = -1.185 m ? your answer may be positive or negative, depending on the direction of the force. express your answer numerically in newtons to
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Coulomb's law for the magnitude of the force f between two particles with charges q and q′ separated...
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