Aproton is accelerated from rest through a potential difference v0 and gains a speed v0. if it were accelerated instead through a potential difference of 2v0, what speed would it gain? a proton is accelerated from rest through a potential difference and gains a speed . if it were accelerated instead through a potential difference of , what speed would it gain? v02√ 4v0 8v0 2v0 submitreques

The speed is .

(a) is correct option.

Explanation:

Given that,

Potential difference

Speed

If it were accelerated instead

Potential difference

We need to calculate the speed

Using formula of initial work done on proton

We know that,

Put the value into the formula

....(I)

If it were accelerated instead through a potential difference of , then it would gain a speed will be given as :

Using an above formula,

Put the value of

Hence, The speed is .

seeing the graph would

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j