In a 100. m race, marge crosses the finish line after 10.8 s. accelerating uniformly, marge took 2.20 s to attain maximum speed, which she maintained for the rest of the race. what was marge's acceleration?

3.50 m/s^2

Explanation:

the race is of 100 m.

time after which Marge crosses the finish line after t= 10.8 sec

time take by her to attain maximum speed t_o= 2.20 sec

a=

we know that

s= ut +1/2at^2

100= v

put a= here t_o= 2.20 sec

v= 7.72 m/s

now Marge acceleration a= = 3.50 m/s^2

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