(1 point) a gun has a muzzle speed of 90 meters per second. what angle of elevation θ, where 0≤θ≤π4, should be used to hit an object 200 meters away? neglect air resistance and use g=9.8m/sec2 as the acceleration of gravit

0.122 radians

Explanation:

Given that the muzzle speed is,

And the distance of the object is,

And acceleration due to gravity is

Therefore negative acceleration due to gravity for upward motion.

Now,

The x component of velocity will be,

The y component of velocity will be,

And the horizontal displacement is given. Now horizontal displacement is,

Here, is horizontal velocity and t is time.

Substitute all the values in above equation, we get

Now, in y direction we can calculate displacement and in y direction displacement is zero.

Substitute all the variables.

Therefore the required angle of elevation is 0.122 radians.

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//