How do you isolate t (time) in this equation? the question is asking me to derive an equation for time to hit the ground for a dropped object in terms of height of the drop, gravity, and initial velocity and that’s what i have so far.

Fine, so we have the equation

S = So + Vo.t + at²/2

We have the final height = 0 and since its dropped, Vo = 0, our a will be the gravity, negative since its falling

0 = So + 0.t - gt²/2

0 = So - gt²/2

Since So is our h, lets change the letter

0 = h - gt²/2

gt²/2 = h

gt² = 2h

t² = 2h/g

t =

overcharge is the right answer system

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.