Kathy tests her new sports car by racing with stan, an experienced racer. both start from rest, but kathy leaves the starting line 1.00 s after stan does. stan moves with a constant acceleration of 3.9 m/s^2 while kathy maintains an acceleration of 4.73 m/s^2. (a) find the time at which kathy overtakes (b) find the distance she travels before she catches him (c) find the speeds of both cars at the instant she overtakes him.

(a) 10 s

(b) 236.5 m

(c) Kathy's speed = 47.3 m/s

    Stan's speed = 42.9 m/s

Explanation:

Given:

Assumptions:

Part (a):

 Kathy will catch Stan only if the distances traveled by each of them are equal at the same instant.

Hence, Kathy catches Stan after 11 s from the Stan's starting times.

Part (b):

Distance traveled by Kathy to catch Stan will be distance the distance traveled by her in 10 s.

Hence, Kathy traveled a distance of 236.5 m to overtake Stan.

Part (c):

The speed of Kathy at the instant she catches Stan is 47.3 m/s.

The speed of Stan at the instant Kathy catches him is 42.9 m/s.

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.  

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000