Amass hanging from a spring is set in motion and its ensuing velocity is given by v(t) = - 41 sin it for t20. assume that the positive direction is upward and s(0) = 4. a. determine the position function for t20. b. graph the position function on the interval 0,3). c. at what times does the mass reach its lowest point the first three times? d. at what times does the mass reach its highest point the first three times?

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Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.